Question

Please help: Convert the following cartesian coordinate into polar coordinate. (-sqrt2,sqrt2)

Answer 1

these are the possible answers:

2, pi/4

2, 3pi/4

4, pi/4

4, 3pi/4

Answer 2

i thought it was 3pi/4,7pi/4

Answer 3

so you have (x,y)
you want to find (r,theta)
\[r=\sqrt{x^2+y^2}\]
and since our point is in the second quadrant to find theta you do
\[\theta=\arctan(\frac{y}{x})+\pi\]

Answer 4

you can also put +2pi to follow any of those for the theta part
since going a full rotation after that point takes you back to that point