Question

Find the indefinite integral. \int [x^{2}+\frac{1}{3x^2}]dx

Answer 1

\[\int\limits_{?}^{?}\left[ x^2+\left(\begin{matrix}1 \\ 3x^2\end{matrix}\right) \right]dx\]

Answer 2

\[=\int\limits x^2~dx+\frac{ 1 }{ 3 }\int\limits x ^{-2}dx+c\]
\[\int\limits x^n dx=\frac{ x ^{n+1} }{ n+1 }\]

Answer 3

Thank you.

Answer 4

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