Solve by elimination: 4a/3 - b/4 =6 5a + b = 13
this Is me
a=3b16+92
a=3b/16+92
number 2 is a=−b5+135
@templeguy how did you get a=3b/16+92
that's number 2 a=-b/5+13/5
@Luigi0210 can you please help me with this?
Have you tried getting rid of b?
No, because I don't understand how to.
Okay, so we have \(\Large \frac{4}{3}a - \frac{b}{4}= 6\) \(\Large 5a+b =13\) ---------------------------- So to eliminate b, we need to get of that fraction, so we multiply by 4: \(\Large \frac{16}{3}-b =16 \) \(\Large 5a+b=13 \) --------------------------- Now we can use elimination :P
-b=16- 16/3 b=13-5a
@Luigi0210 right? ^
Whoops, I forgot my a there.. but close enough. When you cancel the b's, you'll end up with: \(\large \frac{16}{3} a=16 \) \(\large 5a=13 \) ------------------------------------------ Now just add them: \(\Large \frac{16}{3}a +\frac{15}{3} a =13+16\) \(\Large \frac{31}{3}a =29 \) ------------------------------------------- This is looking weird but the answer will for a will be.. : \(\Large a=29*\frac{3}{31} \) \(\Large a=\frac{87}{31} \) Hmm, well I guess that's it for a >.<
Isn't it supposed to be 16/3b not a ?
We're solving for a tho. For elimination, you "eliminate" one of the variables, which was b, so we could solve for the other
ohh okay
now is the next step to sub in 87,31 into the first equation?
a=87/31 **
Yup, and that would give you the other variable.
Hold on tho, I messed up on the calculations somewhere :/
kk..
You at least understand the basic steps for solving using elimination right?
yea i understand it a little bit
would i have to bring 4(87/31)/3 to the other side to make it negative? : -b/4= 6 -4(87/31)/3
...to isolate b
@Luigi0210 what am i supposed to do next
Okay, sorry about that wait.. so attached I have the solution that I came up with. I tried showing the steps. And also, Wolfram confirms it's right :) http://www.wolframalpha.com/input/?i=solve+4a%2F3+-+b%2F4+%3D6+and+5a+%2B+b+%3D+13
That should be 152, not 53, sorry
Oh cool. So, the poi is (111/31, -152/31)
Thanks a millionnnnnnnnnnnn
I'm having so much trouble with math lately lol
No problem, that's why I'm here to try and help if I can :P
Well, thank you for being so caring :)
Yup, good luck :D
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