Question

PLease help! how to solve y = x^3 - 3x + 2 for x and y intercepts. I forget what the method is to find the x-intercepts.

Answer 1

Hello mapletree!

When you're trying to find the x-intercepts, it means where on the graph does the function touches the x-axis. When you touch the x-axis, there's is no "height," so your y will be 0. Set the equation to equal to 0, and solve for x.

As for y, the concept is similar. You're trying to find where on the graph the function crosses the y-axis. The y-axis is located at 0/origin of the x-axis, so set your x's to 0, and you'll be able to solve for y easily!