Question

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Roy exclaims that his quadratic with a discriminant of −9 has no real solutions. Roy then puts down his pencil and refuses to do any more work. Create an equation with a negative discriminant. Then explain to Roy, in calm and complete sentences, how to find the solutions, even though they are not real.

Answer 1

so you want b^2-4ac to be negative
choose values for a and b and c such that this is true
you want to chose a and b and c such that 4ac is bigger than b^2

Answer 2

then put your a,b,c here:
ax^2+bx+c=0
and show roy how to solve it

Answer 3

Ok @freckles , I got a= -3, b = -5, and c = 1

Answer 4

So that,
b^2 -4ac
-5 -4(-3)(1)
25 - 12 = 13