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If ƒ(x )= 2x^2 + 3, then ƒ(x - 1)= 2x^2 + 4x + 5. True False
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@manumben
plug in 2(x-1)^2 + 3, and simplify.
Idk how to do these
2((x-1)(x-1))+3
..?
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are you familiar with the FOIL concept?
(x-1)(x-1) = x^2 - 2x +1
2x^2-4x+2+3 = 2x^2-4x+5
is 2x^2-4x+5 = 2x^2 +4x + 5
Thanks
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