Question

Identify the solutions of 3x^2 − 13x + 4 = 0.

x = −1 over 3, x = −4
x = 1 over 3, x = 4
x = −4 over 3, x = −1
x = 4 over 3, x = 1

Answer 1

do ou know quadratic formual

Answer 2

No what is that?

Answer 3

factor

Answer 4

x = [-b +-square root (b^2 -4ac) ]/ 2a

Answer 5

what does that mean??

Answer 6

In your equation a=3
b= -13 and
c =4

Answer 7

So x = [13 +-sq root(169 -4*3*4)]/2*3
Can you calculate it from there?

Answer 8

yes thank you so much

Answer 9

Okay
and just to check your answer you can go here:
http://www.1728.org/quadratc.htm

Answer 10

C right?

Answer 11

factor

Answer 12

c?

Answer 13

\[(3x-1)(x-4)=0\] and go from there

Answer 14

no

Answer 15

\[x-4=0\\
x=4\]

Answer 16

\[3x-1=0\\
3x=1\\
x=\frac{1}{3}\]

Answer 17

Its B ya?