Simplify the following expression.
2.(a+bc)+cb+ab+ac-3(ab-cb-ba+bc)
A.
3a + 3bc + 2ac + 2ac
B.
2a + 2bc + ab + ac
C.
2a + 3bc + ab + ac
D.
2a + 2bc + cb + ab + ac
i really dont get it wen is letters only invol plz some one explain me
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OpenStudy (mchilds15):
Oh jesus. Hold on, i'll try to help
OpenStudy (anonymous):
@iGreen. plz help
OpenStudy (anonymous):
ok @Mchilds15
OpenStudy (mchilds15):
Follow the PEMDAS
OpenStudy (anonymous):
ok
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OpenStudy (mchilds15):
Parenthesis first. So 3(ab-cb-ba+bc) would simplify to ?
OpenStudy (anonymous):
That's -3(ab - cb - ba + bc)
OpenStudy (mchilds15):
@iGreen. do you want to take this one? It kind of makes me want to bang my head against a wall, typing it out and all
OpenStudy (anonymous):
Which gives us:
\(-3ab + 3cb + 3ba - 3bc\)
Now we have:
\(a+bc+cb+ab+ac-3ab + 3cb + 3ba - 3bc\)
Sure thing @Mchilds15
OpenStudy (anonymous):
ok
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OpenStudy (anonymous):
Combine like terms(they have the same variables)
\(bc + cb + 3cb - 3bc = ~?\)
\(ab - 3ab + 3ba=~?\)
This is the same thing as adding regular numbers but we put the variable next to it.
1 - 3 + 3 = ?
OpenStudy (anonymous):
ok some time i get very confius thats why but thx @iGreen.