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Mathematics 11 Online
OpenStudy (anonymous):

Simplify the following expression. 2.(a+bc)+cb+ab+ac-3(ab-cb-ba+bc) A. 3a + 3bc + 2ac + 2ac B. 2a + 2bc + ab + ac C. 2a + 3bc + ab + ac D. 2a + 2bc + cb + ab + ac i really dont get it wen is letters only invol plz some one explain me

OpenStudy (mchilds15):

Oh jesus. Hold on, i'll try to help

OpenStudy (anonymous):

@iGreen. plz help

OpenStudy (anonymous):

ok @Mchilds15

OpenStudy (mchilds15):

Follow the PEMDAS

OpenStudy (anonymous):

ok

OpenStudy (mchilds15):

Parenthesis first. So 3(ab-cb-ba+bc) would simplify to ?

OpenStudy (anonymous):

That's -3(ab - cb - ba + bc)

OpenStudy (mchilds15):

@iGreen. do you want to take this one? It kind of makes me want to bang my head against a wall, typing it out and all

OpenStudy (anonymous):

Which gives us: \(-3ab + 3cb + 3ba - 3bc\) Now we have: \(a+bc+cb+ab+ac-3ab + 3cb + 3ba - 3bc\) Sure thing @Mchilds15

OpenStudy (anonymous):

ok

OpenStudy (anonymous):

Combine like terms(they have the same variables) \(bc + cb + 3cb - 3bc = ~?\) \(ab - 3ab + 3ba=~?\) This is the same thing as adding regular numbers but we put the variable next to it. 1 - 3 + 3 = ?

OpenStudy (anonymous):

ok some time i get very confius thats why but thx @iGreen.

OpenStudy (anonymous):

Oh, okay

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