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i need help solveing log2x=4
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\[\log_{2} x=4\]
What do you think is the answer?
i was think it mightbe -16
This is how you change from a log equation to an exponential equation. \(\log_b x = y \iff b^y = x\)
When you take the logarithm of a number base b, you are asking the question, what exponent do I raise base b to, to get the number. The logarithm is an exponent.
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\(\log_2 x = 4\) means "what number, x, is the same as base 2 raised to the 4th power"?
ok so x would be 4
i got it x is 16
Correct. Log base 2 of 16 is 4 because 2^4 = 16.
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