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Mathematics 19 Online
OpenStudy (anonymous):

i need help solveing log2x=4

OpenStudy (anonymous):

\[\log_{2} x=4\]

OpenStudy (yolo_king):

What do you think is the answer?

OpenStudy (anonymous):

i was think it mightbe -16

OpenStudy (mathstudent55):

This is how you change from a log equation to an exponential equation. \(\log_b x = y \iff b^y = x\)

OpenStudy (mathstudent55):

When you take the logarithm of a number base b, you are asking the question, what exponent do I raise base b to, to get the number. The logarithm is an exponent.

OpenStudy (mathstudent55):

\(\log_2 x = 4\) means "what number, x, is the same as base 2 raised to the 4th power"?

OpenStudy (anonymous):

ok so x would be 4

OpenStudy (anonymous):

i got it x is 16

OpenStudy (mathstudent55):

Correct. Log base 2 of 16 is 4 because 2^4 = 16.

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