88 coins are worth $14.80 the coins are nickels and quarters. how many nickels and how many quarters?
okay lets see 14.80 divided by 5 (nickels) is 269.... so we need to group nickels into groups of five until there are only 88 coins
... right mr.billj5
I don't know fancy math vocabulary
oh you don't need the actual answer?
there is only one solution
I think
ok, yes i don't care so much for the answer just how you set up the system?
oh...yeah can help you there im sorry
ah, ty, yes im very bad at algebra
let no. of nickels=x no. of quarters=y x+y=88 ...(1) .05 x+0.25 y=14.80 5x+25y=1480 x+5y=296 ...(2) (2)-(1) gives 4y=296-88=208 y=52 x=88-52=36
@surjithayer ty, but i dont understand this
@surjithayer can you please explain it to me
nvm, got it ty
one nickel=5 cents x nickels=5x cents=0.05 x dollars one quarter=25 cents y quarters=25 y cents=0.25 y dollars now x+y=88 and 0.05 x+0.25 y=14.80
thank you :)
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