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OpenStudy (anonymous):
88 coins are worth $14.80
the coins are nickels and quarters.
how many nickels and how many quarters?
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OpenStudy (bobobox):
okay lets see 14.80 divided by 5 (nickels) is 269.... so we need to group nickels into groups of five until there are only 88 coins
OpenStudy (bobobox):
... right mr.billj5
OpenStudy (bobobox):
I don't know fancy math
vocabulary
OpenStudy (bobobox):
oh you don't need the actual answer?
OpenStudy (bobobox):
there is only one solution
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OpenStudy (bobobox):
I think
OpenStudy (anonymous):
ok, yes i don't care so much for the answer just how you set up the system?
OpenStudy (bobobox):
oh...yeah can help you there im sorry
OpenStudy (anonymous):
ah, ty, yes im very bad at algebra
OpenStudy (anonymous):
let no. of nickels=x
no. of quarters=y
x+y=88 ...(1)
.05 x+0.25 y=14.80
5x+25y=1480
x+5y=296 ...(2)
(2)-(1) gives
4y=296-88=208
y=52
x=88-52=36
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OpenStudy (anonymous):
@surjithayer ty, but i dont understand this
OpenStudy (anonymous):
@surjithayer can you please explain it to me
OpenStudy (anonymous):
nvm, got it ty
OpenStudy (anonymous):
one nickel=5 cents
x nickels=5x cents=0.05 x dollars
one quarter=25 cents
y quarters=25 y cents=0.25 y dollars
now x+y=88
and 0.05 x+0.25 y=14.80
OpenStudy (anonymous):
thank you :)
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