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Well it's really hard to see anything.. But, from what I see, the red area is bounded by a line that intersects with the y-axis at y=3. (passes through the point (0, 3)). The bounded area is also beneath the the line, so for a given 'x' the inequality would match for any 'y' value that is smaller than the one of the line. So let's look at the inequalities where 'y' is smaller then something and try to examine which would give y < 3 for x = 0. We can see that at D we have \(y < 4x + 3\), plugging x=0 yields what we wanted. This is the only one that works.. but we can still check the second equality there \(y > -3x + 4\) and see that it matches the blue line's y intersect at y=4 as well.
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