Question

IN A RIGHT TRIANGLE, AN ACUTE ANGLE HAS A TANGENT OF 1/3. FIND THE VALUE OF SEC AND SIN OF THIS ANGLE.
USE PYTHAGOREAN IDENTITIES
I got sec= (radical 10)/3
I can't figure out how to find sin??

Answer 1

By Pythagorean Theorem
hypotenuse^2 = opp^2+adj^2
hypotenuse^2 = 9 + 1
hypotenuse^2 = 10
hypotenuse = sqrt 10

sine = opp/hyp
sine = 1 / sqrt(10)

Answer 2

isnt the hypotenuse (radical 10)?
because secant is (hypotenuse/adjacent)
and my answer was (radical 10) / 3

Answer 3

Yes, doesn't radical 10 = square root of 10?

Answer 4

secant = hyp/adj

secant = sq root (10) / 3 or
radical 10 / 3

Answer 5

ok thank you

Answer 6

u r welcome