IN A RIGHT TRIANGLE, AN ACUTE ANGLE HAS A TANGENT OF 1/3. FIND THE VALUE OF SEC AND SIN OF THIS ANGLE.
USE PYTHAGOREAN IDENTITIES
I got sec= (radical 10)/3
I can't figure out how to find sin??

Question

IN A RIGHT TRIANGLE, AN ACUTE ANGLE HAS A TANGENT OF 1/3. FIND THE VALUE OF SEC AND SIN OF THIS ANGLE.
USE PYTHAGOREAN IDENTITIES
I got sec= (radical 10)/3
I can't figure out how to find sin??

wolf1728 · Answer

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By Pythagorean Theorem 
hypotenuse^2 = opp^2+adj^2
hypotenuse^2 = 9 + 1
hypotenuse^2 = 10
hypotenuse = sqrt 10

sine = opp/hyp
sine = 1 / sqrt(10)

anonymous · Answer

isnt the hypotenuse (radical 10)?
because secant is (hypotenuse/adjacent)
and my answer was (radical 10) / 3

wolf1728 · Answer

Yes, doesn't radical 10 = square root of 10?

wolf1728 · Answer

secant = hyp/adj

secant = sq root (10) / 3 or
radical 10 / 3

anonymous · Answer

ok thank you

wolf1728 · Answer

u r welcome