If 5t = 45 and tk = 1, what is the value of k? And how? a. 1/45 b.1/9 c.1/5 d.5 e.9
first solve for t in the first equation \(5t = 45 \) we want just the \(t\) and not \(5t \), so what are we going to do?
that = to 9
I dont understand your equation
5t=45 t=9
oh okay then use that value of \(t \) to solve for the k \(9k =1 \), similarly, we just want k so what are we going to do?
turn it into a fraction?
it is not a matter of turning it into fraction, but notice something we are always diving in the case of your problem and dividing follows the fractional form \(\huge \frac{p}{q} \) where p is the numerator and q is the denominator
oh ok thanks
so it follows, that in order to solve for k is to divide \(9t \) by its coefficient \(9 \) as well as the right-hand side of the equation by that same divisor
easy peachy ain't it?
yes thank you
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