Question

What is the equation of a line passing through the point (a, b) and having a slope of b?

Answer 1

There are two other answers.

Answer 2

y=1/bx+b(a-1)
y=-1/bx+b(1-a)

Answer 3

y = −bx − b(1 − a)
y = bx − b(a − 1)

Answer 4

@mathmath333

Answer 5

\(\large \begin{align} \color{black}{\normalsize \text{general formula}\hspace{.33em}\\~\\
y-y_1=m(x-x_1) \hspace{.33em}\\~\\
\normalsize \text{equation of line passing through points (a,b)}\hspace{.33em}\\~\\
\normalsize \text{and having a slope of b is}\hspace{.33em}\\~\\
y-b=b(x-a) \hspace{.33em}\\~\\
\normalsize \text{try to match it with ur options or simplify }\hspace{.33em}\\~\\
}\end{align}\)

Answer 6

Don't forget to close this post if you're done.
Thanks! :3

Answer 7

I'm not done, I still don't get it. @arabpride

Answer 8

what do you not get @peytonamberxoxo

Answer 9

To solve for the equation of a line when a slope, m, is provided and a point (x1, y1), use the point-slope formula

y-y1= m(x-x1) and then solve for y

Answer 10

In your problem,
Slope= b
Point (a,b)

Use the point-slope form
(y-b) = b(x-a)
Use distributive property in the right-hand side of the equation:
(y-b) = bx - ba
Then solve for y to get the equation the line using the slope-intercept form
y = bx - ba + b