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Mathematics 17 Online
OpenStudy (k_lynn):

Converting standard form to slope-intercept form.

OpenStudy (k_lynn):

http://prntscr.com/64kmwl

OpenStudy (misty1212):

HI!!

OpenStudy (k_lynn):

hiya :)

OpenStudy (misty1212):

you want to make this look like \(y=mx+b\) right?

OpenStudy (k_lynn):

right.

OpenStudy (ribhu):

standard slope intercept form is y=mx+c

OpenStudy (misty1212):

start with \[15x-5y=25\] and solve for \(y\) in two steps

OpenStudy (ribhu):

see that you get y on your left hand side.

OpenStudy (misty1212):

subtract \(15x\) to get \[-5y=-15x+25\]

OpenStudy (ribhu):

-5y = 25-15x

OpenStudy (misty1212):

nvm

OpenStudy (ribhu):

divide by 5 both the sides

OpenStudy (ribhu):

-y = 5 - 3 x

OpenStudy (ribhu):

multiply by -1both the sides

OpenStudy (k_lynn):

I'm not getting this at all.

OpenStudy (ribhu):

y = 3x - 5 , equation of straight line with slope = 3 and intercept = -5. which step u didn't get @k_lynn

OpenStudy (misty1212):

HI again

OpenStudy (misty1212):

suppose you wanted to solve \[15-5x=25\]for \(x\) what would you do?

OpenStudy (ribhu):

see first tell me if u know what is slope intercept form of equation.

OpenStudy (k_lynn):

wait is this how to do it? |dw:1423836006850:dw|

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