EASY QUESTION- MEDAL when doing basic algebraic expressions, how do you multiply variables? i.e. 3y * 5y i am having the worst brain fart ever right now it is not even funny
first multiply 3*5
so its just 15y?
then multiply y*y = (y^1)(y^1)
Fairly certain it's \[3y * 5y = 15y^{2}\]
Multiply the whole numbers together, then the variables.
@Nibby Please do not give answers, it's against OpenStudy's Code-of-Conduct. We are here to guide the asker to the answer, so we need his/her participation. http://openstudy.com/code-of-conduct
then y^(1+!) = y^2
Because: \[5 * 3 = 15\] and: \[y * y = y^{2}\]
I was getting to it @iGreen.
then the answer becomes 15 y^2
so 3*5 = 15 and y*y = y^2 so 15y^2?
@iGreen. LOL your doing it also -_-
ok, thank you all its been a long week haha
@Nibby \(\color{blue}{\text{Originally Posted by}}\) @iGreen. @Nibby Please do not give answers, it's against OpenStudy's Code-of-Conduct. We are here to guide the asker to the answer, so we need his/her PARTICIPATION. http://openstudy.com/code-of-conduct \(\color{blue}{\text{End of Quote}}\)
I didn't do anything.. @Shikatanori all I said was: \(\color{blue}{\text{Originally Posted by}}\) @iGreen. Multiply the whole numbers together, then the variables. \(\color{blue}{\text{End of Quote}}\) She gave the answer..
oh god please dont start another one of these fueds on my post
I didnt say here ? :3
did u get it? @kah.x
Why did you restate the CoC response? @iGreen. I explained it soon after, apologies.
Yes, but you weren't supposed to give it without the asker's participation.
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Just Add the variables exponent @kah.x
then multiply the numerical value
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