Solve The Equation Algebraically 3x^2=12
what are the answer choices?
+3 +2 3.5 1.5
I got X=2
How'd You Do It ?
Yeah x = 2. You multiply 3 and 2 and you get 6 right? Well then to equal 12, x has to equal 2, so the answer is x = 2.
So On This On 2x^2=98 It Would Be 2*2 = 4 & Then To Equal 98 It Would Be x=94 ? @aaronq @CanadianSteve99
No, you would need to multiply 4 times a number to equal 98. If a variable (letter) is beside a number, like 2x = 18, then x would be 9 and you would multiply 2 and 9. You multiply 4 times x to equal 98.
Sorry if I over complicated that xD
Yeah Just A Little @CanadianSteve99
Basically just multiply 4 times x, or divide 98 by 4.
so when solving algebraic equations, you need to isolate the unknown variable (in this case it's x). you need to perform the inverse operations, for example if it's x/3=2, then you need to multiply both sides by 3. for you question: \(3x^2=12 \) divide both sides by 3: \(\dfrac{\cancel 3x^2}{\cancel 3}=\dfrac{12}{3} \) then take the square root of both sides: \(\sqrt x^2=\sqrt 4\) we're left with: \(x=2\)
So The Square Root Of 12 ? @aaronq
it's not the squared root of 12, but of \(\dfrac{12}{3}\) which is 4. so it's the squared root of 4, look at the first step
Okay Okay So 12\ 3 = 4 & The Square Root Of 4 Is 2 Right ?
yes and yes
Okay I Think I Get It But Just To Make Sure If Its 2^2=98 Id Divide Both Sides By 2 Then Divide 98 & 2 I Got 49 & The Square Root Of 49 Is 7 Right ?
was the original equation \(2x^2=98\) i think you missed the x in your expression.
Yeah It Was
than it is correct, good job on applying the process. \(\huge \checkmark\)
then*
Ahaa Thanks So Much , Couldnt Do It Without Your Help
no problem, really! i gotta get going though, hopefully someone else can keep helping you, take care!
Okay Thanks !
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