Question

Using a directrix of y = -2 and a focus of (2, 6), what quadratic function is created?

Answer 1

@Directrix

Answer 2

Also
\(\huge\color{Blue}{WELCOME~TO~OPENSTUDY!!!! }\)

Answer 3

Do you have equations as options or perhaps just the name of the type curve described?

@snugglemuffinman

Answer 4

yes I equations to choose from they are :

Answer 5

\[f(x) = -1/8 (x-2) ^ 2-2\]

Answer 6

f(x) = 1/16 (x-2)^2 -2

Answer 7

\[f(x) = 1/8 (x-2)^2 -2\]

Answer 8

\[f(x) = -1/16 (x+2) -2\]

Answer 9

@Directrix

Answer 10

y = -2 and a focus of (2, 6),

Answer 11

2?

Answer 12

hmmm 2? is it? how so?

Answer 13

oh wait no is it 4?

Answer 14

ok.. .how did you get 4?

Answer 15

counted the distance from -2 to the vertex

Answer 16

do you know what the directrix is? or the focus point?

or maybe you need to refresh that section of the chapters first

Answer 17

ohhh... ok.. .so do you know where the vertex is then?

Answer 18

the distance is 9? from -2 to 6? And the vertex is it at 2?

Answer 19

@jdoe0001

Answer 20

@Destinymasha @nincompoop @pooja195 someone please help..... I will give a medal

Answer 21

@Abhisar

Answer 22

was a bit lagged, thus

Answer 23

6 from the 2 marker and 2 from -2 to 2? Sorry im really bad at this