Question

How would I write an equation of a line in standard form with a slope of -8 and passing through the point (-10, 2).

Answer 1

HI!!

Answer 2

put it in the point-slope form, since you are given a point and a slope

Answer 3

hey Misty:] so what would that look like?

Answer 4

do you know what the point slope form looks like?

Answer 5

y-y1=m(x-x1)

Answer 6

yeah
plug in the numbers in the the appropriate spots

Answer 7

it says in standard form so i'm confused?

Answer 8

you are not there yet
you have to do this first

Answer 9

go ahead plug the numbers in to the point slope form, then we can write it in "standard form"

Answer 10

y- 2=-8(x- -10)

Answer 11

ok good
now distribute on the right

Answer 12

im lost I don't know how I would get this in standard form?

Answer 13

we are working towards that
be patient dear it takes a few steps \(\color\magenta\heartsuit\)

Answer 14

use the distributive property to remove the parentheses on the right side of the equal sign

Answer 15

y- 2=-8x- (-10)

Answer 16

also you probably want to start with
\[y-2=-8(x+10)\]

Answer 17

now distribute the \(-8\) on the right side

Answer 18

you know what i am saying?
\[a(b+c)=ab+ac\] is the distributive law

Answer 19

so what is
\[-8(x+10)\]?

Answer 20

-8x+10

Answer 21

oh no lets try again

Answer 22

\[a(b+c)=ab+ac\] not \(ab+c\)

Answer 23

-80x +10

Answer 24

you just erased the parentheses, you did not distribute

Answer 25

\[-5(x+3)=-5x-15\] for example

Answer 26

-8x -80

Answer 27

yay

Answer 28

\[y-2=-8x-80\] now add \(2\) to both sides

Answer 29

y=-8x+82

Answer 30

hmm what is \(-80+2\)?

Answer 31

-78

Answer 32

ok so one more step
we have
\[y=-8x-72\]

Answer 33

to put in in standard form, add \(8x\) to both sides

Answer 34

8x+y=-78

Answer 35

now we are done!

Answer 36

that's it? haha you made it so easy!:]

Answer 37

\[\color\magenta\heartsuit\]

Answer 38

thank you so much hun!:]