[Help me - Reward ( Medal and Fan) How much Aluminium will be required to cover a cylinderical flask of length 30 cm??
the volume should be calculated.. V=pi*R*R*h assuming unit radius V=3.14*1*1*.3=.942
[2pirh + 2piR^2?\] @MARC_
cover you mean outer covering? if its the outer covering it should be surface area.. then its 2*pi*r*h + 2*pi*r*r =1.84 + 6.28 =8.122
The base and lid are not made of aluminium @MARC_ @rohitmathew
that makes it just the lateral surface.. assuming unit radius.. the answer would be 1.84
IS THE RADIUS GIVEN?
oh well if the base and lid aren't made of aluminium it would just be the rectangular side that is aluminium :) So since the length is 30, this means you would use 2pi*r*h so 2pi*r*30 . And then we'd need to know the radius or else we can't solve :)
The Radius isnt given :( @rohitmathew @butterflydreamer
what about.. a diagram or the diameter? :O
u need to put some value for the radius to get a numerical answer.. or the answer would be in terms of the the variable R something like 1.84R..
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