Question

The graph below shows the velocity f(t) of a runner during a certain time interval:

graph of line going through ordered pairs 0, 4 and 4, 8. Graph of another line going through ordered pairs 4, 8 and 8, 0. Label on the x axis is time in second and label on the y axis is velocity in meter per second

Which of the following describes the intercepts on the graph?

The initial velocity of the runner was 4 m/s, and the runner stopped after 8 seconds.
The initial velocity of the runner was 8 m/s, and the runner stopped after 4 seconds.
The initial acceleration of the runner was 4 m/s2,

Answer 1

@Nnesha
@hartnn
@ganeshie8 @TuringTest @Godlovesme

Answer 2

@SyedMohammed98

Answer 3

y-intercepts are always initial points :) @heypeeps1234

Answer 4

ok @Godlovesme

Answer 5

@mathslover @uri @thomaster

Answer 6

initial mean where ur start graph start
beginning point
y -axis is velocity

Answer 7

ok @Nnesha

Answer 8

so look at the graph and see at what point that line starting

Answer 9

8 @Nnesha

Answer 10

nope :(

Answer 11

this point

Answer 12

y-axis is represent velocity

Answer 13

and remember y-intercept is always on y-axis

Answer 14

4 @Nnesha @SyedMohammed98

Answer 15

yes

Answer 16

it can't be the last one because according to the formula
final velocity - initial velocity/time will give u 1 m/s^2

Answer 17

I believe that we can eliminate b and d right

Answer 18

@Nnesha @SyedMohammed98

Answer 19

initial = starting point
y-intercept = starting point

Answer 20

ok

Answer 21

y-intercept starting point on the graph*

Answer 22

I be love it is c am i right ?

Answer 23

so u r left with the first two options.....the initial velocity is 4m/s so it's the first one :)

Answer 24

you just have 3 answer choices right ??

Answer 25

well.............
initial = starting point like i said point
so if you look at the graph starting point is 4