Question

Use chain rule to find partial derivative w.r.t x of
f(x,y) = (x^2+y^2) sin(1/(x^2+y^2))
Please, help

Answer 1

I stuck at find df/dx (1/ x^2+y^2)

Answer 2

for partial, we see y as constant, hence just (1/x^2 + constant^2))'

Answer 3

\(\frac {\partial f}{\partial x} (\dfrac{1}{x^2+y^2})\) Just this part.

Answer 4

Apply chain rule, please.

Answer 5

@zepdrix derivative-expert, please help

Answer 6

got it :)