Question

PLEASE HELP sqrt - 9 / (3-2i)+(1+5i)

Answer 1

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Answer 2

choices
a . 12 - 9i / 25
B. 12-9i / 7
C. 9+12i / 25
D. 9+12i / 7

Answer 3

your help is very much appreciated

Answer 4

@jim_thompson5910

Answer 5

So you are doing:
\[\frac{\sqrt{-9}}{3-2i}+(1+5i)\]

Answer 6

the bottom is set up as (3-2i)+(1+5i)
so idk if thats the same as that or not

Answer 7

That looks right though

Answer 8

So you mean the problem is:
\[\frac{\sqrt{-9}}{(3-2i)+(1+5i)}\]

Answer 9

Yes!

Answer 10

no this expression and the expression you gave aren't equivalent
it is like saying 1/1+2 is the same as 1/(1+2)
and we know 1+2 isn't the same as 1/3
because 1+2 is 3 and 1/3 doesn't equal 3
---
but any who...
do you know the square root of 9?

Answer 11

3

Answer 12

\[\sqrt{-1}=i\]
so I'm going to rewrite this as :
\[\frac{\sqrt{9} i}{(3-2i)+(1+5i)}=\frac{3i}{(3-2i)+(1+5i)}\]

Answer 13

so on bottom you have 3+1 and -2i+5i

Answer 14

do you know how to find those sums

Answer 15

No :(

Answer 16

oh I don't believe that 3+1 equals...

how many circles do you see in all