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Mathematics 15 Online
OpenStudy (anonymous):

Help! attached document

OpenStudy (anonymous):

OpenStudy (anonymous):

Can anyone help me with this?

OpenStudy (michele_laino):

please use this formula: \[y = Ax + B\] furthermore, note that your line passes at points (-2,0) and (0,2)

OpenStudy (anonymous):

The possible answers are A. x ≤ 3 B. x ≥ 3 C. x ≤ −3 D. x ≥ −3

OpenStudy (anonymous):

I dont understand how I find the answer

OpenStudy (michele_laino):

Please can you write the text of your problem?

OpenStudy (anonymous):

What do you mean?

OpenStudy (michele_laino):

I mean the text of your exercise on your textbook

OpenStudy (michele_laino):

I'm sorry I see it

OpenStudy (anonymous):

it is about domain range and function

OpenStudy (anonymous):

ok

OpenStudy (michele_laino):

the domain of a function are all possible values of the independent x-variable, for which our function is defined

OpenStudy (michele_laino):

more precisely the domain of a function is the set of all possible values of the x-variable

OpenStudy (anonymous):

okay

OpenStudy (michele_laino):

so, for what values of the x-variable your function is defined?

OpenStudy (anonymous):

-2?

OpenStudy (anonymous):

-2 and 2?

OpenStudy (michele_laino):

no, because also at x=-3 your function is defined

OpenStudy (michele_laino):

furthermore also at x= 4, 5, 6... your function is defined

OpenStudy (michele_laino):

hint: at x= -4 is your function defined?

OpenStudy (anonymous):

no?

OpenStudy (anonymous):

so x is greater than 3?

OpenStudy (michele_laino):

so x greater or equal than -3

OpenStudy (michele_laino):

since at x=-3 the value of your function is -1

OpenStudy (anonymous):

so my answer would be x>-3?

OpenStudy (michele_laino):

not exactly, please retry

OpenStudy (anonymous):

less than -3?

OpenStudy (michele_laino):

no, since for all x such that x< -3 your function is not defined

OpenStudy (michele_laino):

or in other words, for all x such that x< -3 your function doesn't exist

OpenStudy (anonymous):

so would you take away the negative?

OpenStudy (anonymous):

sorry, I am confused

OpenStudy (michele_laino):

don't worry, please note that, we have established that: 1) for all x such that x< -3 your function doesn't exist 2) at x= -3, your function does exist, and its value is -1 3) your function also does exist for all x such that x is Greater or equal than -3 so what is your answer?

OpenStudy (anonymous):

x>3?

OpenStudy (michele_laino):

and at x= -3 your function does exist?

OpenStudy (anonymous):

Yes

OpenStudy (michele_laino):

then, what is your answer?

OpenStudy (anonymous):

my answer wouldnt be x>3?

OpenStudy (anonymous):

x<3?

OpenStudy (michele_laino):

I think that your function does exist at x = -3 and does not exist for all x such that x <-3

OpenStudy (anonymous):

My possible answers are A. x ≤ 3 B. x ≥ 3 C. x ≤ −3 D. x ≥ −3

OpenStudy (michele_laino):

whereas your function does exist for allx such that x x>3

OpenStudy (michele_laino):

please see your drawing

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