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Solve using substitution. 5x + 12y = 146 x - 12y = -158
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First find the value of x in terms of y. \(\sf x+158=12y\\ \Rightarrow x=12y-158\)
Now substitute this value of x in other equation.
5(12y-158)+ 12y = 146 60y-790+12y=146 72y-790=146
is that right so far?
yes
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72y-790=146 add 790 to both sides 72y=-644 this is the part i get stuck on
when i divide I get a fraction =/
\(\sf 72y=146+790 \\ \huge y = \frac{146+790}{72}\)
oh whoops 936/72=13 yay!! i got :D
so y=13
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wait now im confused where would i sub?
:(
Yes, y =13. Now substitute this value of y in any of the original equations and calculate the value of x
x=12y−158 x=12(13)-158 x=156-158 x=-2?
Correct :)
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