Question

Factor the binomial completely. 4m^3+108.
PLEASE HELP, I don't get this.

Answer 1

So you should know the rule (a+b)^3 and (a-b)^3 - In this case we have the binomial but we have to work it out backwards. So, we can do 4(m+3) <-- now we got the 1st part of our answer. Now we need to look at the number 108. We know that is dividable by 3 and that makes it to the rule (a-b)^3 so we get 4(m+3)(m^3-3m+9) as our final answer.

Hope that helps.


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Answer 2

Oops! Should've been 4(m+3)(m^2-3m+9)

Answer 3

https://www.khanacademy.org/math/algebra2/polynomial_and_rational/factoring-higher-deg-polynomials/v/factoring-sum-of-cubes

Try this, and you'll learn something. Just getting the answer shouldn't cut it.