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Mathematics 8 Online
OpenStudy (anonymous):

what is the value of x in the diagram? A. 1/2 B. 4/21 C. 2 D. 4 I HAVE NO IDEA WHAT I AM DOING! :(

OpenStudy (anonymous):

OpenStudy (anonymous):

Same question. A. 15 B. 5 2/5 C. 19 D. 3/5

OpenStudy (anonymous):

What similarity statement can you write relating the three triangles in the diagram?

OpenStudy (anonymous):

what is the geometric mean between 5 and 12? how? multiply 5 and 12 = 60 and take the square root. 2 square root 15

OpenStudy (anonymous):

What are the values of x and y?

OpenStudy (anonymous):

Maggie has a kite with the dimensions shown below. What is the width of the kite?

OpenStudy (anonymous):

@pooja195 can you help?

OpenStudy (anonymous):

@CausticSyndicalist

OpenStudy (anonymous):

Anyone!!!!!!!!!!!!!!!!!!!!!!!!!

OpenStudy (anonymous):

@Tootles143

OpenStudy (anonymous):

@ILUVSOCCER There you go...

OpenStudy (anonymous):

Which diagram?

OpenStudy (anonymous):

All!

OpenStudy (iluvsoccer):

Ai Mija this is so hard hehe, Sorry :(

OpenStudy (anonymous):

Well may you give me the first one?

OpenStudy (anonymous):

what do u mean... its the top they go in order

OpenStudy (iluvsoccer):

@Sparklestaraa here haha

OpenStudy (anonymous):

PLease stay and try @ILUVSOCCER :'( I dont want to leave her alone....

OpenStudy (iluvsoccer):

Bon chance mon ames

OpenStudy (iluvsoccer):

I'll try but i'll just guess and with my little known knowledge

OpenStudy (sparklestaraa):

jaja Oui Bonne Chance XD Mon math est mauvais!

OpenStudy (iluvsoccer):

Haha okay yeah au revoir then mon ami

OpenStudy (sparklestaraa):

Vous parlez pas français?

OpenStudy (sparklestaraa):

*francais

OpenStudy (iluvsoccer):

Oui Mademoiselle, but don't use this as a chatbox

OpenStudy (iluvsoccer):

let me try and so;ve this and talk later

OpenStudy (anonymous):

WTF!!!!!! I don't ask anyone for help this is the first time I really need it!!!!!!!!!!!!!!!PLEASE!!!

OpenStudy (iluvsoccer):

Okay I'll grab mon ames real quick or espanol mi amigos

OpenStudy (anonymous):

Sorry... Im trying... No need to be rude! :'(

OpenStudy (sparklestaraa):

Tres Bien, nous allons parler personnellement plus tard.

OpenStudy (iluvsoccer):

@ganeshie8 @Luigi0210 @confluxepic, Please help her :)

OpenStudy (sparklestaraa):

@jim_thompson5910 @MARC_

OpenStudy (iluvsoccer):

@TheSmartOne or @undeadknight26, help please monsieurs

OpenStudy (anonymous):

im sorry @Tootles143 im I just need this! Im really sorry

OpenStudy (anonymous):

No its okay... I get that way too...

OpenStudy (sparklestaraa):

@bunnyrabbit41414 FLVS or LS? This will help me help u and ur grade level is it Algebra 1?

OpenStudy (anonymous):

@ambius

OpenStudy (sparklestaraa):

@MARC_ Help her real quick

OpenStudy (anonymous):

geometry

OpenStudy (sparklestaraa):

Oh hey www.mathway.com ;)

OpenStudy (sparklestaraa):

www.wolframalpha.com :P

OpenStudy (anonymous):

This is about grade 9 or 10 stuff; mostly similar triangles - which means is can mostly be done with algebra.

OpenStudy (anonymous):

@Lonniedos @alimcewen @HelpBlahBlahBlah @jim_thompson5910

TheSmartOne (thesmartone):

Eh...

TheSmartOne (thesmartone):

Too many questions, a different language in this post. Super confused what has to be done and what haasn't...

TheSmartOne (thesmartone):

hasn't*

TheSmartOne (thesmartone):

This should help you... http://www.mathsisfun.com/geometry/triangles-similar.html

OpenStudy (anonymous):

all the questions on what I posted before any one got on ay itnd okay ill try

OpenStudy (anonymous):

okay no not going to help me idk what im doing what so ever

OpenStudy (anonymous):

I believe I got the first one. I show you how I did it:

OpenStudy (anonymous):

awesome ty

OpenStudy (anonymous):

Similar triangles by side-angle-side relationship... so the small triangle at the top is equal to the big triangle around the whole outside. therefore, the ratio of the small triangle (LENGTH of right side divided by LENGTH left side) is EQUAL to the ratio of the big triangle (LENGTH of right side divided by LENGTH of left side). That gives you the following: \[\frac{ 12 }{ 9} = \frac{ 3x + 2 + 12 }{ 4x - 2 + 9 }\] See how the big triangle includes the lengths of the sides of the smaller triangle? That's because the whole large triange is similar to the whole small triangle.

OpenStudy (anonymous):

Solve for x, and you'll get your answer.

OpenStudy (anonymous):

can u help me with the other ones.. ik thats alot to ask but im a blonde and my hair seriously gets to me

OpenStudy (anonymous):

I could definitely help with a few. Just give a me couple of seconds, as I got a couple people asking for my attention, lol. How about the second one? You have that one yet?

OpenStudy (anonymous):

no i have the one u helped with and what is the geometric mean between 5 and 12? how? multiply 5 and 12 = 60 and take the square root. 2 square root 15

OpenStudy (anonymous):

that looks right to me. you multiply the two numbers, then take their root, which is sqrt(60). or 2*sqrt(15).

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

??

OpenStudy (anonymous):

I'm looking at the second problem, but it doesn't appear to be 2 similar triangles... it seems a bit trickier; looking for a solution though.

OpenStudy (anonymous):

KK

OpenStudy (anonymous):

@whydoihavetosignup1

OpenStudy (anonymous):

HELLOO:)

OpenStudy (anonymous):

Hey. :D I got an answer for number 2 the ...complicated way using geometry. However, if this problem is supposed to be simpler, then I'm certain the ratios are supposed to be: \[\frac{ 9 }{ x } = \frac{ 15 }{ 25 }\] But there's a reason I doubt myself... but it's the best I can come up with at the moment given my divided attention, lol

OpenStudy (anonymous):

3rd question is about congruency of the two triangles (Hint. Angle-side-angle)

OpenStudy (anonymous):

look at multiple choices im confused on the .................. dude..... idk i think ima just fail

OpenStudy (anonymous):

the next one: \[12^{2} + h^{2} = y^{2}\] \[16^{2} + h^{2} = x^{2}\] \[x^{2}+y^{2} = (12+16)^{2}\] these 3 equations manipulated should help you find the answer.

OpenStudy (anonymous):

to all three?

OpenStudy (anonymous):

I wouldn't be so quick to say you'll fail. I barely passed highschool math, now I'm in school for engineering, lol. Yeah, it's not easy to get know... but later you'll look back, and wonder why it was so tough... Just don't talk yourself out of it. XD

OpenStudy (anonymous):

what about 4 5 6

OpenStudy (anonymous):

no, the last one were all equations to solving 5.diagram.png.

OpenStudy (anonymous):

those three equations are needed to solve it. If you look in the diagram, there are 3 right triangles.

OpenStudy (anonymous):

i want to be a doctor.. so im trying but cant get the hang of it

OpenStudy (anonymous):

and ok

OpenStudy (anonymous):

cool. when I'm done engineering, I'm going to apply to med school; so I think we're kinda in the same boat. XD

OpenStudy (anonymous):

lol cool:)

OpenStudy (anonymous):

did you get an answer for diagram 5?

OpenStudy (anonymous):

im confused?

OpenStudy (anonymous):

@serenacox

OpenStudy (anonymous):

that will explain it for ya

OpenStudy (anonymous):

okay.

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