Question

P and Q are any 2 points lying on the sides DC and AD respectively of a parallelogram ABCD. show that ar(APB)=ar(BQC).

Answer 1

Can you draw a rough figure for this?

Answer 2

Good, so, now we need to prove Ar(APB) = Ar(BQC)

We know that Area of a Triangle = \(\cfrac{1}{2} \times \text{Base} \times \text{Height} \)

Answer 3

Also, area of a parallelogram = Base * Corresponding Height

So, area of parallelogram ABCD = AB * PQ

Answer 4

Sorry, you can use R instead of Q.
So, for AB as the base you've Area of Parallelogram = AB * PR