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If y = 3x^3 – 2x and dx/dt = 3, find dy/dt when x = –2.
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@hartnn @Luigi0210 @paki @Destinymasha @confluxepic @sammixboo @Nnesha @undeadknight26 @eliassaab
\[\frac {dy}{dt} = 6 x^2 \frac {dx}{dt} - 2 \frac {dx}{dt} \]
You have x= -2 and dx/dt=3, replace and you will be done.
102?
its 9x^2-2
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@eliassaab
\[ 6 (-2)^2 (-3)- 2(-3)=-66 \]
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