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find the solution of 15y-y^2=0
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\[\Large\rm 15y-yy=0\]Take a y out of each term,\[\Large\rm y(\qquad ?\qquad)=0\]What are we left with in the brackets? :o Remember how to factor?
take y common y(15-y) = 0 so now either y can be zero or 15-y should be zero. so y = 0, 15
@mcnabkt your solution with explanation.
\[15y-y^2=0 \\y(15-y)=0\\y=0 \vee y=15\]
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im lost....
why?
because math is like a puzzle to me
helpppp
Look at the attachment I put up there ^ @mcnabkt it shows the steps it takes
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@TheSmartOne
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Look at this @mcnabkt:
Hi there :)
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