Mathematics
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OpenStudy (shelby1290):
Solve by substitution:
a+b=5
3a+4b=15
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OpenStudy (sleepyjess):
What do you want to solve for first, a or b?
OpenStudy (shelby1290):
I'll go with a
OpenStudy (sleepyjess):
Ok, so we need to get b on one side. The first equation will probably be easiest to do this with.
OpenStudy (shelby1290):
so like: b=5a ?
OpenStudy (sleepyjess):
Close, good try :) It would actually be b = 5 - a since we need to subtract a
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OpenStudy (shelby1290):
alright
OpenStudy (sleepyjess):
Now, substitute that in for b in the second equation.
OpenStudy (shelby1290):
3(5-a)+4b=15
OpenStudy (sleepyjess):
That equation equals b, not a :)
OpenStudy (shelby1290):
okay 3(5-b)+4b=15 ...right?
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OpenStudy (sleepyjess):
3a + 4(5 - a) = 15
OpenStudy (shelby1290):
ohhh
OpenStudy (shelby1290):
3a+20-4a=15
OpenStudy (sleepyjess):
Do you get why I put it in for b though?
OpenStudy (shelby1290):
yes i do
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OpenStudy (sleepyjess):
that is correct, now just solve for a
OpenStudy (shelby1290):
-1a=15-20
OpenStudy (sleepyjess):
Yep, so -a = -5. Now we need to multiply the entire thing by -1 to get positive a
OpenStudy (shelby1290):
a=5
OpenStudy (sleepyjess):
Yes! Now we can substitute in 5 for a in either of the equations and get b
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OpenStudy (shelby1290):
I can't tell if it's easier to plug it into the 1st equation or the 2nd
OpenStudy (sleepyjess):
The first probably, all that is in the first is just subtracting from both sides
OpenStudy (shelby1290):
okay so 5+b=5
bring 5 to the other side....
5-5=0
OpenStudy (shelby1290):
b=0
OpenStudy (shelby1290):
so therefore the poi is (5,0)
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OpenStudy (shelby1290):
@sleepyjess thanks for the help!
OpenStudy (sleepyjess):
yep, that is correct, sorry, was afk for a little bit :)