Question

ANYONE HELP WIT DIS QUESTION I GIVE MEDAL$$$ http://gyazo.com/e8d25ee676cec1a6b404490dbe4d1369

Answer 1

Please you have to evaluate x and y at t=2, so you have to set t=2 into the formulas for x and for y

Answer 2

@Michele_Laino and what i come up with?

Answer 3

the magnitude of your position vector is given by the subsequent formula:
\[\sqrt {{x^2} + {y^2}} \]
where x and y are the components of the position vector evaluated at t= 2

Answer 4

and? i came up with that now go on? sstill alittle confused i must didnt do it right

Answer 5

please what is x(2)=?

Answer 6

i came up with 12.2 m

Answer 7

sorry, please I aked you what is x(2)

Answer 8

oops.. I asked...

Answer 9

hint:
x(2) = 2^2 + 2*2 +1 =...?

Answer 10

please hold

Answer 11

10

Answer 12

x(2) = 4+4+1=9

Answer 13

so my answer would be? 12.2

Answer 14

and what is y(2)?
hint:
y2) = 3*(2^2) + 3*2 -2...?

Answer 15

please note that I can not give you the final answer directly since the Code of Conduct

Answer 16

16

Answer 17

that's right!
Now what is:
\[\sqrt {{9^2} + {{16}^2}} \]

Answer 18

18.4

Answer 19

@Am4n* why did you givve out the answer?

Answer 20

hint:
9^2 = 81, and:
16^2 = 256

Answer 21

so:
\[\sqrt {{9^2} + {{16}^2}} = \sqrt {81 + 256} = ...?\]

Answer 22

trying to find out

Answer 23

18.35

Answer 24

that's right!

Answer 25

Please note that 18.35 can be rounded off to 18.4

Answer 26

yea. i did that and got the answer

Answer 27

thanks!!!!!!! can you help me again with a problem?

Answer 28

yes!