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For which system of equations is (–2, 2) the solution? A. 3x – 5y = –16 –2x + 3y = 10 B. –4x + 2y = 6 2x – 3y = 10 C. 4x + 3y = 2 5x + 4y = –2 D. 6x + 5y = –2 –8x + 5y = –6
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substitute x=-2 into the equations
if u get y=2,that will be ur correct equation
Let's check one by one
Option A...
\[3x-5y=-16\]\[-2x+3y=10\]
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|dw:1424267681255:dw|
substitute x=-2 into the equation
\[3(-2)-5y=-16\]\[-2(-2)+3y=10\]
if u get y=2,that equation is correct
\[-6-5y=-16\]\[4+3y=10\]
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i know it not B bc it just doesn't have y=2
\[-5y=-16+6\]\[3y=10-4\]\[-5y=-10\]\[3y=6\]\[y=2,y=2\]
its C!
nope
Option B...
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\[-4x+2y=6\]\[2x-3y=10\]\[-4(-2)+2y=6\]\[2(-2)-3y=10\]
\[8+2y=6\]\[-4-3y=10\]
its A?
\[2y=6-8\]\[-3y=10+4\]
yep :)
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thank you so much!
yw!
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