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b = 9, c = 16 a =
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Pythagorean Theorem? a^2 + b^2 = c^2
Pythagorean theorem \(a^2 + b^2 = c^2\) Plug in 'b' and 'c': \(a^2 + 9^2 = 16^2\) Solve for 'a'
a^2+81=256
Yes, now subtract 81 to both sides what's 256 - 81?
A^2=168
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256 - 81 doesn't equal 168
i mean 169
No, check again
Take the square root of 169.
175
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Yes, now find the square root of 175 and you have your answer.
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