According to Josh’s measurement, the distance from his house to the baseball practice field is 4 km. The actual distance is 3.68 km.
What was the percent error in Josh’s measurement? Round to the nearest tenth of a percent, if needed.
A. 0.3%
B. 8%
C. 8.7%
D. 32%
PLZ HELP I WILL GIVE OUT MEDAL!!!
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OpenStudy (anonymous):
@sleepyjess
OpenStudy (anonymous):
thx @PlanSlam
OpenStudy (anonymous):
how did u get b
OpenStudy (anonymous):
i am just askin
OpenStudy (anonymous):
there u go
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OpenStudy (anonymous):
i guess
OpenStudy (anonymous):
@PlanSlam how did u get b i am just askin so i can know @sleepyjess
OpenStudy (anonymous):
Ok this problem works like this. I am going to use counting numbers, which makes it simpler I think.
Lets say we measured 4 but the actual measurement was 2 . First fine the difference
4 - 2 = 2
Now what percent of 4 is 2. This is like saying what fraction of 4 is 2
2 / 4 = 1/2 = .5 = 50%
The problem you have works the same way
4 - 3.68 = .32
Can you finish the rest?
OpenStudy (anonymous):
@OpenStudyBot
OpenStudy (anonymous):
u r the best thx i am 99.9998999989% sure that i got it know
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