Question

9x^3+18x^2-x-2

Answer 1

medal for answer

Answer 2

what 's the question ?
is it : to find roots ?

Answer 3

The Factor Theorem says that if you can find a number that makes your polynomial=0, then x- that number is a factor
For 9x^3+18x^2-x-2
-2 gives it a value of 0
9(-2)^3+18(-2)^2-(-2)-2
=-72+72+2-2
=0
Therefore x-(-2) is a factor
Now x-(-2) is x+2
Divide the poyynomial by (x+2) and you get
(x+2)(9x^2-1)
=(x+2)(3x-1)(3x+1)

By the way, finding the -2 is a matter of trying several numbers until you find one that works

Answer 4

hint:
\(9x^3+18x^2-x-2 = 9x^2(x+2) - (x+2)\)
Try extract common factor that you see.

Answer 5

and do not forget to continue searching for other patterns such as difference of two squares.