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Hi, can you look at this problem? squareroot X+5 - squareroot x-3 = 4
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yeah \[\sqrt{x+5}-\sqrt{x-3}= 4\]
yes, How should I start off?
take sqrt x-3 to rhs, then square both the sides
alright
\[x+5= 4/x+9\]
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x+5 = (4 + sqrt x-3)^2 not that u wrote.
ops lol
x + 5 = 7 +x
2x = 12
x = 6?
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no
ops
x+5 = 16+3+x
x+5 = 16+x-3+8sqrt x-3
no what r u doin
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x+5= 4^2 + squareroot x -3
x+5 = 16 +x+3
no its that what i wrote.
x= 4
but squarerrot (x-3)^2 = x+3
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how do you get what you got?
no its x-3
my bad
yeah.
ok so x+5=16+x-3
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and+8sqrtx-3
on the rhs
how? do you get that?
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