Mathematics
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OpenStudy (study_buddy99):
trig help?! (picture to be posted in the comments)
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OpenStudy (study_buddy99):
|dw:1424304569706:dw|
OpenStudy (anonymous):
still there?
OpenStudy (study_buddy99):
yes
OpenStudy (anonymous):
okay
OpenStudy (anonymous):
you can use pythagorean theorem to find the hypotenuse
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OpenStudy (study_buddy99):
but what about the other angles?
OpenStudy (anonymous):
find the third side first, then use sine law
OpenStudy (anonymous):
a^2+b^2=c^2
c is the hypotenuse
OpenStudy (study_buddy99):
|dw:1424306208025:dw|
OpenStudy (anonymous):
okay, then use sine law
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OpenStudy (study_buddy99):
how?
I always get confused on this part.
OpenStudy (study_buddy99):
that made me even more confused
OpenStudy (anonymous):
ill help you, w8
OpenStudy (anonymous):
it says that
a/sin A = b/sin B = c/sin C
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OpenStudy (anonymous):
meaning, the side opposite of the angle is proportional and equal to other ratio of angle to side
OpenStudy (anonymous):
5.83/ sin 90 = 5/Sin x
find the angle
OpenStudy (anonymous):
still there?
OpenStudy (study_buddy99):
yes, trying to understand
OpenStudy (anonymous):
to find the angle, x = inv sin (5 (sin 90)/ 5.83)
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OpenStudy (anonymous):
so the angle directly opposite to 5 is 59 degrees
OpenStudy (anonymous):
OpenStudy (study_buddy99):
I got 5.83 for some reason
OpenStudy (anonymous):
got the angle now?
OpenStudy (study_buddy99):
no
I still keep getting 5.83
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OpenStudy (anonymous):
study the sine law.
OpenStudy (study_buddy99):
thank you