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How do you solve this question? The question is attached as an image.
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if you plugged in x = t, you'd get 0/0 which is indeterminate but there is a way to fix this. You somehow have to cancel out the (t-x) in the denominator. So that means you have to somehow find a way to factor out (t-x) in the numerator
yeah that's where i got stuck on. how do you factor 4t^(1/3) - 4x^(1/3) ?
like i know you have to take the 4 out but i'm not sure what your supposed to do with the exponent
*you're
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I'm still working that part out. One sec
ok
Have you learned about the difference of cubes factoring formula?
ohh yes a^3 – b^3 = (a – b)(a^2 + ab + b^2)
correct
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we don't have something of the form a^3 - b^3, but we do have something similar
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