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Mathematics 13 Online
OpenStudy (gnrfan):

Help with math

OpenStudy (anonymous):

yes?

OpenStudy (arabpride):

What do ya need? :3

OpenStudy (gnrfan):

here it is

OpenStudy (gnrfan):

As one of the new roller coaster engineers, you have been tasked with developing a roller coaster that will intertwine with existing Oakville Lake Amusement Park structures. For one of the more thrilling sections, the roller coaster will dive down in-between buildings, plummet underground, pop back up, and coast over a hill before shooting back underground. There must be three distinct points where the roller coaster crosses the x–axis. Precise measurements and attention to detail are very important. coordinate plane with buildings blocking off x–intercepts of negative 11, negative 10, 0, 1, 2, 3, 9, and 10 First, here is the existing map of current structures. It is important that the roller coaster does not go through the foundation of any of these structures. 1st point: ___6___ 2nd point:___-2___ 3rd point: ___-7___ Using the points above as zeros, construct the polynomial function, f(x), that will be the path of your roller coaster. Show all of your work. Root 6 has a factor of (x-6), root -2 has a factor of (x-(-2)), and root -7 has a factor of (x-(-7)). Multiplying (x-6) and (x+2), I get x^2-4x-12. Then I multiply by (x+7), so (x^2-4x-12)(x+7). Then I get the function of f(x)=x^3 + x^2-28x-12x-84 Using both fundamental Theorem and Descartes` rule of signs, prove to the construction foreman that your function matches your graph. Use complete sentences. Solve for the y–intercept for your function, f(x), and then construct a rough graph of your roller coaster. If your y–intercept is off the graph, give the coordinates of the y–intercept.

OpenStudy (gnrfan):

hold on while i get the pic, 1 sec

OpenStudy (gnrfan):

@arabpride can you help?

OpenStudy (gnrfan):

@Nishant_Garg I just need help with the last two

OpenStudy (anonymous):

The function you got by multiplying the 3 factors, didn't it work?

OpenStudy (gnrfan):

Not sure, I got this far from another person and they just left after the 1st question

OpenStudy (gnrfan):

It did work but I have to prove it A.K.A have my math teacher put another pointless hurdle

OpenStudy (anonymous):

check out this link http://www.wolframalpha.com/input/?i=x%5E3%2Bx%5E2-28x-12x-84

OpenStudy (anonymous):

look at the graph

OpenStudy (gnrfan):

what am i lookin for?

OpenStudy (gnrfan):

I still don't understand...

OpenStudy (anonymous):

actually it should be \[x^3+3x^2-40x-84\] instead of \[x^3+x^2-40x-84\]

OpenStudy (anonymous):

see if the graph from wolfram fits your graph, (it should not cross any building)

OpenStudy (gnrfan):

they both work

OpenStudy (gnrfan):

so what does this give me, sorry for being clueless but this is like trying to smell a sound to me

OpenStudy (anonymous):

I'm not sure but I guess you've got your function from multiplying the 3 factors \[f(x)=x^3+3x^2-40x-84\] It is intersecting at (6,0),(-2,0),(-7 ,0)as required and you've got your rough graph.

OpenStudy (anonymous):

graph from wolfram

OpenStudy (gnrfan):

so whats the answer?

OpenStudy (anonymous):

I don't think its crossing any building aswell

OpenStudy (gnrfan):

is it the expression next to the graphs on the website?

OpenStudy (anonymous):

your answer would be \[f(x)=x^3+3x^2-40x-84\] and that graph from wolfram I'm not sure though, is there anything else that's required

OpenStudy (gnrfan):

ok so the f(x) equation for the 2nd to last question and the graph for last?

OpenStudy (anonymous):

yeah I guess

OpenStudy (gnrfan):

THANK YOU SO MUCH MAN, IVE BEEN TRYING TO SOLVE THIS FOR A MONTH AND NO ONE WOULD HELP!!!

OpenStudy (anonymous):

oh my god, one month???

OpenStudy (gnrfan):

and two others. every one just gives up and leaves

OpenStudy (anonymous):

no need to worry now, you can always find help over here at this website

OpenStudy (gnrfan):

k can you help me with the other two later

OpenStudy (gnrfan):

or now?

OpenStudy (anonymous):

Not right now, I'm studying but you can always ask your question here just close this one and post a new one if you need more help

OpenStudy (gnrfan):

okay, good luck man

OpenStudy (anonymous):

Also don't ask for answers here, we prefer it here to guide people to the answers

OpenStudy (gnrfan):

I know just my teacher was starting to get mad and I needed it quick

OpenStudy (anonymous):

don't worry about it too much, nobody is going to ask for your homework after school

OpenStudy (gnrfan):

I do online schooling so my teacher just threatens to drop me from the class

OpenStudy (anonymous):

oh..

OpenStudy (anonymous):

Ive heard about home schooling, but online schooling, that's hardcore man

OpenStudy (anonymous):

You should check out Khan Academy if you study online

OpenStudy (gnrfan):

yea. im not really a fan of her, a week without turning in assignments is pretty much termination

OpenStudy (anonymous):

@gnrfan have you tried Khan Academy before?

OpenStudy (gnrfan):

ive been on that before, its ok

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