What is the domain of the function? y= sqrt sign 4x-4
@undeadknight26
If this is how the function looks like \[y=\sqrt{4x-4}\] then 4x-4 must be grater or equal 0. Solve it.
I has no idea...
No worries @undeadknight26 and @konrad509 im not sure how to solve it that's why I posted :) could you walk me through the steps?
\[4x-4\geq0\] You have to solve this inequality. It's very basic and trivial stuff. You should know how to do it...
Sorry im not at smart as the average person I guess. Math is not my forte
The options are a.) x>-1 b.) x is greater than or equal to 1 c.) x is greater than or equal to -1 d.) x>1
@YOLO_KING can you help me out? :)
The answer is b because you are putting the grater than or equal to zero before the 2x-2 then you add 2 to 0 which gets you positive two. now you divide 2x with two; and you get the answer b. make sence
Are you positive? :) Thank you!!
Yes I am positive and you are welcome
The domain is \[[1,\infty \infty),{x|x \ge1}\] answer^^^
In other words b Lol
Thanks guys! I have 5 more problems is anyone down to earn five more medals? :)
Yep
Join our real-time social learning platform and learn together with your friends!