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Mathematics 7 Online
OpenStudy (anonymous):

What is the value of the first quartile (Q1) of the data set? The graph is in the comments below.

OpenStudy (anonymous):

@Agl202

OpenStudy (anonymous):

First you have to find Q2, which is the median of the data set. Can you do that?

OpenStudy (anonymous):

I need help understanding it.

OpenStudy (anonymous):

Do you understand how to read that stem and leaf plot in the link?

OpenStudy (anonymous):

The line represents the stem and the numbers represent the leaves. Right @jwhite12 ?

OpenStudy (anonymous):

The numbers in the left column represent the tens, and the numbers on the right side are the ones digits. So the first couple of numbers in your data set are: 45, 51, 52, 58, ...

OpenStudy (anonymous):

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OpenStudy (anonymous):

I still don't get it. @jwhite12

OpenStudy (anonymous):

Can you write out all the numbers from your data set?

OpenStudy (anonymous):

I think the answer is 45. That's the first set of numbers.@jwhite12

OpenStudy (anonymous):

45 is the first number in the set, but it's not the first quartile.

OpenStudy (anonymous):

I'm confused.@jwhite12

OpenStudy (anonymous):

The first thing you need to do is read the stem/leaf plot and write out the list of numbers it represents. I started this list for you earlier. 45, 51, 52, 58... Can you finish that list?

OpenStudy (anonymous):

Is it 3? @jwhite12

OpenStudy (anonymous):

|dw:1424378165317:dw|

OpenStudy (anonymous):

So no?

OpenStudy (anonymous):

not 3

OpenStudy (anonymous):

So your list of numbers is: 45, 51, 52, 58, 61, 63, 66, 72, 74

OpenStudy (anonymous):

Before finding Q1, you have to find Q2 -- which is the MIDDLE number of the data set. Can you find Q2?

OpenStudy (anonymous):

So the answer would be 61? @jwhite12

OpenStudy (anonymous):

Yes, Q2 is 61. Now to find Q1, we just look at the numbers to the left of Q2. So we're looking at: 45, 51, 52, 58

OpenStudy (anonymous):

To find Q1, you do what we did a minute ago but now we're finding the median of that smaller set.

OpenStudy (anonymous):

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