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solve: log4(x+1) + log4(x-1) = 6. I'm not sure how to get the 6 to a log4 base... thanks!
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first look at some rules for log\[\huge\rm \log ~x + \log~ y = \log (x \times y)\] \[\large\rm log ~x - \log~ y = \log \frac{ x }{ y }\] so there is plus sign how would you change that ??
log4[(X+1)(x-1)] = 6 ? it's the 6 that's throwing me off..
haha okay you have to change logarithmic to exponential form
|dw:1424377874450:dw| right side number become exponent of base and move left side number to the right side like tin this example
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