Question

"You have a 61.9-mF capacitor initially charged to a potential difference of 10.3 V. You discharge the capacitor through a 3.47-Ω resistor. What is the time constant? After what multiple of the time constant does the potential difference reach 2.45 V?"

I'm having some trouble with the "multiple of time constant" idea. I really don't understand what the question is asking me for.

Answer 1

I know that I'm using this equation
\[\Delta V = V _{o}e ^{\frac{ -t }{ \tau }} \]
But I don't know which part is considered the "multiple of the time constant".