Question

5^(x −x^2) = 1/ (625^x) solve the equation for x, smaller value and larger value.... I really don't get this one :(

Answer 1

I know 625 can be written as 25^2
and 25 can be written as 5^2
\[625=25^2=(5^2)^2=5^4\]
And you have in your problem\[\frac{1}{625^x}=625^{-x}=(5^4)^{-x}=5^{-4x}\]

Answer 2

hope that helps

Answer 3

Thank you so much