Question

Find the point(0,b) on the y-axis that is equidistant from the points (3, 3) and (6, -5).
b=

Answer 1

may i??

Answer 2

May you help? Is that what your asking?

Answer 3

yeah!

Answer 4

sure, be my guest xp

Answer 5

let the point be (0,b)

Answer 6

calculate the distance between ( 0,b) and (3,3) sqrt ((3-0)^2+(3-b)^2)

Answer 7

similarly between (0,b) and (6,-5) which is sqrt ((6-0)^2+(-5-b)^2)

Answer 8

since the point is equidistant from both the points so the distances must be equal.
9+9+b^2-6b = 36+25+b^2+10b; thiscan be solved for b

Answer 9

ok thnx, i get it now, ill solve for b now.

Answer 10

ok i got 0= 43 + 16b -2b^2
i got stuck

Answer 11

-18 =16b

Answer 12

how did you get that?

Answer 13

only solving the equation which i wrote

Answer 14

never mind i see what i did wrong, i put -b^2 instead of +b^2

Answer 15

i got -43 = 16b

Answer 16

sorry u r correct

Answer 17

aha.....thnx for the help XD