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Verify this trigonometric identity.
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where is the function?
\[\frac{ (\sin t+\cos t)^2 }{ \sin t \cos t } = 2+\sec t \csc t\]
So far I have \[\frac{ \sin ^{2}t+\cos ^{2}t }{ \sin t \cos t }+2 = 2+\sec t \csc t\]
Verify means prove LHS = RHS, not solve
correct
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looks right to me
I need to get to the point where one side equals the other.
From the LHS, the numerator: sin^2+ cos^2 + 2sincos =1 + 2 sincos now combine with the denominator, you have|dw:1424483601530:dw|
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