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Mathematics 8 Online
OpenStudy (sparklestaraa):

help

OpenStudy (sparklestaraa):

OpenStudy (sparklestaraa):

@jim_thompson5910

jimthompson5910 (jim_thompson5910):

what do you have so far for this?

OpenStudy (sparklestaraa):

nothing ;( i tried looking at it but i can't figure anything to write

jimthompson5910 (jim_thompson5910):

what is the initial amount of lumens we have?

jimthompson5910 (jim_thompson5910):

ie what is the starting amount of light intensity?

OpenStudy (sparklestaraa):

1200

jimthompson5910 (jim_thompson5910):

Correct. Now let's say we travel 1 meter down the cable. What is the intensity now?

OpenStudy (sparklestaraa):

still 1200 ?

jimthompson5910 (jim_thompson5910):

the light decreases 2.5% per meter of cable

jimthompson5910 (jim_thompson5910):

if you take 1200 and decrease it by 2.5%, you get ???

OpenStudy (sparklestaraa):

uhhhh 1200*2.5% correct

jimthompson5910 (jim_thompson5910):

close

jimthompson5910 (jim_thompson5910):

you must do 100-2.5 = 97.5 so you're really multiplying 100 by 97.5%, ie 100*0.975

jimthompson5910 (jim_thompson5910):

oops not 100, 1200

jimthompson5910 (jim_thompson5910):

1200*0.975

jimthompson5910 (jim_thompson5910):

if we want to know the intensity when it goes 2 meters, then we multiply by 0.975 again (to reduce it by 2.5%) 1200*0.975*0.975 = 1200(0.975)^2 do you see a pattern emerging?

OpenStudy (sparklestaraa):

yes somewhat

jimthompson5910 (jim_thompson5910):

if we want to know the intensity when it goes 3 meters, then we multiply by 0.975 a third time 1200*0.975*0.975*0.975 = 1200(0.975)^3 and so on

jimthompson5910 (jim_thompson5910):

how about 4 meters?

OpenStudy (sparklestaraa):

uh maybe

jimthompson5910 (jim_thompson5910):

what do we do if we want to find the intensity for 4 meters?

OpenStudy (sparklestaraa):

the other equation

jimthompson5910 (jim_thompson5910):

what do you mean?

OpenStudy (sparklestaraa):

1200*0.975*0.975*0.975*0.975 = 1200(0.975)^4

OpenStudy (sparklestaraa):

@jim_thompson5910

jimthompson5910 (jim_thompson5910):

correct

jimthompson5910 (jim_thompson5910):

so in general, for x meters, we have 1200*0.975*0.975*0.975*0.975 *0.975*0.975*...*0.975 x copies of 0.975 multiplied

jimthompson5910 (jim_thompson5910):

therefore, in general, the expression is 1200*(0.975)^x

jimthompson5910 (jim_thompson5910):

agreed or no?

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