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OpenStudy (sparklestaraa):
OpenStudy (sparklestaraa):
@jim_thompson5910
jimthompson5910 (jim_thompson5910):
what do you have so far for this?
OpenStudy (sparklestaraa):
nothing ;( i tried looking at it but i can't figure anything to write
jimthompson5910 (jim_thompson5910):
what is the initial amount of lumens we have?
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jimthompson5910 (jim_thompson5910):
ie what is the starting amount of light intensity?
OpenStudy (sparklestaraa):
1200
jimthompson5910 (jim_thompson5910):
Correct. Now let's say we travel 1 meter down the cable. What is the intensity now?
OpenStudy (sparklestaraa):
still 1200 ?
jimthompson5910 (jim_thompson5910):
the light decreases 2.5% per meter of cable
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jimthompson5910 (jim_thompson5910):
if you take 1200 and decrease it by 2.5%, you get ???
OpenStudy (sparklestaraa):
uhhhh 1200*2.5% correct
jimthompson5910 (jim_thompson5910):
close
jimthompson5910 (jim_thompson5910):
you must do 100-2.5 = 97.5
so you're really multiplying 100 by 97.5%, ie 100*0.975
jimthompson5910 (jim_thompson5910):
oops not 100, 1200
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jimthompson5910 (jim_thompson5910):
1200*0.975
jimthompson5910 (jim_thompson5910):
if we want to know the intensity when it goes 2 meters, then we multiply by 0.975 again (to reduce it by 2.5%)
1200*0.975*0.975 = 1200(0.975)^2
do you see a pattern emerging?
OpenStudy (sparklestaraa):
yes somewhat
jimthompson5910 (jim_thompson5910):
if we want to know the intensity when it goes 3 meters, then we multiply by 0.975 a third time
1200*0.975*0.975*0.975 = 1200(0.975)^3
and so on
jimthompson5910 (jim_thompson5910):
how about 4 meters?
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OpenStudy (sparklestaraa):
uh maybe
jimthompson5910 (jim_thompson5910):
what do we do if we want to find the intensity for 4 meters?
OpenStudy (sparklestaraa):
the other equation
jimthompson5910 (jim_thompson5910):
what do you mean?
OpenStudy (sparklestaraa):
1200*0.975*0.975*0.975*0.975 = 1200(0.975)^4
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OpenStudy (sparklestaraa):
@jim_thompson5910
jimthompson5910 (jim_thompson5910):
correct
jimthompson5910 (jim_thompson5910):
so in general, for x meters, we have
1200*0.975*0.975*0.975*0.975 *0.975*0.975*...*0.975
x copies of 0.975 multiplied
jimthompson5910 (jim_thompson5910):
therefore, in general, the expression is 1200*(0.975)^x