Question

Solving Quadratic Equations: Error Analysis

-x^2 + x + 6 = 4
(3 - x) (x + 2) = 4
(3-x) = 4 or (x + 2) = 4
x = 2, or x = -1 the solution checks out.

-x^2 - 3x + 10 = 6
(5 + x) (2 - x) = 6
5 + x = 6 or 2 - x = 6
x = 1 or x = -4. The solution checks out.
But now in the previous problem to make a = -1 if I multiply by -1, we have
x^2 + 3x - 10 = -6
(x+5) (x - 2) = -6
x + 5 = -6 or x - 2 = -6
Solving the equations does not give consistent values for x and y. What went wrong?

Answer 1

IS the formula -b +or - b^2 - 4(a)(c)/2(a)