Question

how do I differentiate the series ab^(a-1) and series ab^a.

Answer 1

\[\sum_{a=1}^{\infty}\]

Answer 2

HI!!

Answer 3

can you be a bit more specific?

Answer 4

hello :)

Answer 5

\[\sum_{n=1}^{\infty}\] really doesn't mean anything by itself

Answer 6

\[\sum_{a=1}^{\infty} a b^{a-1}\]

Answer 7

differentiate term by term

Answer 8

what you wrote is the derivative of
\[\sum_{a=1}^{\infty}b^a\]

Answer 9

so your saying differentiate ab^a would be a^2 * b^(a+1)

Answer 10

no

Answer 11

the derivative of \(b^a\) wrt \(b\) is \( ab^{a-1}\)

Answer 12

the derivative of \(ab^{a-1}\) wrt \(b\) is \(a(a-1)b^{a-2}\)